EXPLOSIVE POWER! (C-4)
Posted: 2005-08-16 17:03
In BF2, the SF class carries around several explosive devices, they are filled with C-4. In this thread, I am going to try and convince the developers to reduce the power of their C-4 charges to purely realistic values. Below, you can find my calculations to find the explosive force of the C-4 used in the game. (SCROLL TO THE BOTTOM TO SKIP THE MATH!!!)
The RC-90 detonator is about 23 cm tall. Using that measurement and this picture: http://files.ea.com/downloads/eagames/o ... onator.jpg
We can calculate the volume of the charge that the player uses.
Volume = LxWxH
V:C4 = 20x18x11.5 cm
V:C4 = 4140 cm3
So, the volume of the C-4 charge in BF2 is about 4140 cm3.
We know that RDX is the primary explosive filler in C-4.
RDX's density if 1.76 grams/cm3. With this, we can find the bomb's RDX mass.
Mass of Bomb's RDX = 1.76g x 4140cm^3 = 7286.4 grams
This would be the bomb's weight if it was 100% RDX, but we know that C-4 is a mixture of RDX and a plasticizer. RDX makes up 91% of the C-4's mass. So, we take 7286.4g x 0.91 = 6630.624g. This is the bomb's approximate amount of RDX: 6630.624 grams.
"Detonation is a process of supersonic combustion that involves a shock wave and a reaction zone behind it. The shock compresses the material thus increasing the temperature to the point of ignition. The ignited material burns behind the shock and releases energy that supports the shock propagation. This self-sustained detonation wave is different from a deflagration that propagates with a subsonic speed and without a shock. Detonations generate high pressures and are usually much more destructive than deflagrations."
RDX's velocity of detonation at a density of 1.76 grams/cm^3 is 8,750 meters per second (m/s). With this information, the detonation force can be found using more formulae. After this, you can use another formula to determine the size of a charge needed to penetrate the armor of an M1A2 Abrams as depicted in the game.
Using the formula (P = R^3*K*C), where:
P = Exp. Required (kg
R = Breaching Radius (m)
K = Material Factor (kg/m^3)
C = Tamping Factor (m)
On the sides of the M1A2, the armor is made up of ceramic blocks set in resin between layers of conventional armor such as steel. The breaching radius of that armor is about 300mm (0.3 m). The material factor is about 27 080 kg/m^3 (DU+Steel+Ceramics). The tamping factor is ruled out since in the game, you don't cover the explosive charge with anything.
P = 0.3m^3 * 27080kg/m^3 = 731.16kg of C-4
731.6kg = = 1612.9 lbs.
So, the final calculation shows that the player would need a 1612.9 pound package of uncovered C-4 to completely destroy an M1A2 Abrams. The player in the game has a bomb that weighs about 14 pounds!
CONCLUSION!
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The power of the SF infantry's C-4 charge in PRMM against the M1A2 tank, needs to be scaled down by a factor of 115 to the side and frontal armor. The tank needs to be vulnerable to engine destruction if the player places C-4 on the engine exhaust of the tank, thus stopping the tank. Hummvees, light vehicles, and infantry should still be very vulnerable to C-4 packs, as they do not have 300mm thick armor. That's my suggestion.
The RC-90 detonator is about 23 cm tall. Using that measurement and this picture: http://files.ea.com/downloads/eagames/o ... onator.jpg
We can calculate the volume of the charge that the player uses.
Volume = LxWxH
V:C4 = 20x18x11.5 cm
V:C4 = 4140 cm3
So, the volume of the C-4 charge in BF2 is about 4140 cm3.
We know that RDX is the primary explosive filler in C-4.
RDX's density if 1.76 grams/cm3. With this, we can find the bomb's RDX mass.
Mass of Bomb's RDX = 1.76g x 4140cm^3 = 7286.4 grams
This would be the bomb's weight if it was 100% RDX, but we know that C-4 is a mixture of RDX and a plasticizer. RDX makes up 91% of the C-4's mass. So, we take 7286.4g x 0.91 = 6630.624g. This is the bomb's approximate amount of RDX: 6630.624 grams.
"Detonation is a process of supersonic combustion that involves a shock wave and a reaction zone behind it. The shock compresses the material thus increasing the temperature to the point of ignition. The ignited material burns behind the shock and releases energy that supports the shock propagation. This self-sustained detonation wave is different from a deflagration that propagates with a subsonic speed and without a shock. Detonations generate high pressures and are usually much more destructive than deflagrations."
RDX's velocity of detonation at a density of 1.76 grams/cm^3 is 8,750 meters per second (m/s). With this information, the detonation force can be found using more formulae. After this, you can use another formula to determine the size of a charge needed to penetrate the armor of an M1A2 Abrams as depicted in the game.
Using the formula (P = R^3*K*C), where:
P = Exp. Required (kg
R = Breaching Radius (m)
K = Material Factor (kg/m^3)
C = Tamping Factor (m)
On the sides of the M1A2, the armor is made up of ceramic blocks set in resin between layers of conventional armor such as steel. The breaching radius of that armor is about 300mm (0.3 m). The material factor is about 27 080 kg/m^3 (DU+Steel+Ceramics). The tamping factor is ruled out since in the game, you don't cover the explosive charge with anything.
P = 0.3m^3 * 27080kg/m^3 = 731.16kg of C-4
731.6kg = = 1612.9 lbs.
So, the final calculation shows that the player would need a 1612.9 pound package of uncovered C-4 to completely destroy an M1A2 Abrams. The player in the game has a bomb that weighs about 14 pounds!
CONCLUSION!
---------------
The power of the SF infantry's C-4 charge in PRMM against the M1A2 tank, needs to be scaled down by a factor of 115 to the side and frontal armor. The tank needs to be vulnerable to engine destruction if the player places C-4 on the engine exhaust of the tank, thus stopping the tank. Hummvees, light vehicles, and infantry should still be very vulnerable to C-4 packs, as they do not have 300mm thick armor. That's my suggestion.